-0.5(10^(2))+40(10)-350=x

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Solution for -0.5(10^(2))+40(10)-350=x equation: 



-0.5(10^(2))+40(10)-350=x

We move all terms to the left:

-0.5(10^(2))+40(10)-350-(x)=0

determiningTheFunctionDomain
-x-350+4010-0.510^2=0

We add all the numbers together, and all the variables

-1x+3659.7399=0

We move all terms containing x to the left, all other terms to the right

-x=-3659.7399

x=-3659.7399/-1

x=3659+0.73990000000003/1

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